Base | Representation |
---|---|
bin | 1001111001010100100… |
… | …11010100101101100111 |
3 | 1012111122000210120122211 |
4 | 10330222103110231213 |
5 | 21032321101000111 |
6 | 420111023504251 |
7 | 33364550243155 |
oct | 4745223245547 |
9 | 1174560716584 |
10 | 340012125031 |
11 | 12121aa87027 |
12 | 55a91458087 |
13 | 260a8568037 |
14 | 126571883d5 |
15 | 8ca028d521 |
hex | 4f2a4d4b67 |
340012125031 has 2 divisors, whose sum is σ = 340012125032. Its totient is φ = 340012125030.
The previous prime is 340012124993. The next prime is 340012125049. The reversal of 340012125031 is 130521210043.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 340012125031 - 231 = 337864641383 is a prime.
It is a super-2 number, since 2×3400121250312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 340012124993 and 340012125011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340012126031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170006062515 + 170006062516.
It is an arithmetic number, because the mean of its divisors is an integer number (170006062516).
Almost surely, 2340012125031 is an apocalyptic number.
340012125031 is a deficient number, since it is larger than the sum of its proper divisors (1).
340012125031 is an equidigital number, since it uses as much as digits as its factorization.
340012125031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 340012125031 its reverse (130521210043), we get a palindrome (470533335074).
The spelling of 340012125031 in words is "three hundred forty billion, twelve million, one hundred twenty-five thousand, thirty-one".
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