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3400441141312 = 2653131892833
BaseRepresentation
bin110001011110111010000…
…101100001100001000000
3110001002010120220221120001
4301132322011201201000
5421203100413010222
611122050250525344
7500450046540265
oct61367205414100
913032116827501
103400441141312
1110a1134414076
1246b040a36854
131b88776859b7
14ba8218cd26c
155d6bec2ae27
hex317ba161840

3400441141312 has 14 divisors (see below), whose sum is σ = 6747750389918. Its totient is φ = 1700220570624.

The previous prime is 3400441141309. The next prime is 3400441141343. The reversal of 3400441141312 is 2131411440043.

It can be written as a sum of positive squares in only one way, i.e., 2475889662016 + 924551479296 = 1573496^2 + 961536^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26565946353 + ... + 26565946480.

Almost surely, 23400441141312 is an apocalyptic number.

3400441141312 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

3400441141312 is a deficient number, since it is larger than the sum of its proper divisors (3347309248606).

3400441141312 is an equidigital number, since it uses as much as digits as its factorization.

3400441141312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53131892845 (or 53131892835 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 3400441141312 its reverse (2131411440043), we get a palindrome (5531852581355).

The spelling of 3400441141312 in words is "three trillion, four hundred billion, four hundred forty-one million, one hundred forty-one thousand, three hundred twelve".

Divisors: 1 2 4 8 16 32 64 53131892833 106263785666 212527571332 425055142664 850110285328 1700220570656 3400441141312