Base | Representation |
---|---|
bin | 100110101010101001100000… |
… | …1101110100011001001000111 |
3 | 1122121020111102010221101201222 |
4 | 1031111103001232203021013 |
5 | 324034403132313102103 |
6 | 3203205451024110555 |
7 | 131432235120445445 |
oct | 11525230156431107 |
9 | 1577214363841658 |
10 | 340113120440903 |
11 | 99409189838087 |
12 | 3219024ba6545b |
13 | 117a16b68004c4 |
14 | 5ddb7c46cdb95 |
15 | 294c1c95a8638 |
hex | 13554c1ba3247 |
340113120440903 has 2 divisors, whose sum is σ = 340113120440904. Its totient is φ = 340113120440902.
The previous prime is 340113120440867. The next prime is 340113120440909. The reversal of 340113120440903 is 309044021311043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 340113120440903 - 216 = 340113120375367 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340113120440909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170056560220451 + 170056560220452.
It is an arithmetic number, because the mean of its divisors is an integer number (170056560220452).
Almost surely, 2340113120440903 is an apocalyptic number.
340113120440903 is a deficient number, since it is larger than the sum of its proper divisors (1).
340113120440903 is an equidigital number, since it uses as much as digits as its factorization.
340113120440903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 340113120440903 its reverse (309044021311043), we get a palindrome (649157141751946).
The spelling of 340113120440903 in words is "three hundred forty trillion, one hundred thirteen billion, one hundred twenty million, four hundred forty thousand, nine hundred three".
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