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340141419521 is a prime number
BaseRepresentation
bin1001111001100100000…
…00100010110000000001
31012111222001002102100122
410330302000202300001
521033102200411041
6420131523030025
733401010235061
oct4746200426001
91174861072318
10340141419521
11121286a66982
1255b0880b315
13260c9297657
141266a4033a1
158cab7ccc4b
hex4f32022c01

340141419521 has 2 divisors, whose sum is σ = 340141419522. Its totient is φ = 340141419520.

The previous prime is 340141419517. The next prime is 340141419523. The reversal of 340141419521 is 125914141043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 339399456400 + 741963121 = 582580^2 + 27239^2 .

It is a cyclic number.

It is not a de Polignac number, because 340141419521 - 22 = 340141419517 is a prime.

Together with 340141419523, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (340141419523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170070709760 + 170070709761.

It is an arithmetic number, because the mean of its divisors is an integer number (170070709761).

Almost surely, 2340141419521 is an apocalyptic number.

It is an amenable number.

340141419521 is a deficient number, since it is larger than the sum of its proper divisors (1).

340141419521 is an equidigital number, since it uses as much as digits as its factorization.

340141419521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 35.

The spelling of 340141419521 in words is "three hundred forty billion, one hundred forty-one million, four hundred nineteen thousand, five hundred twenty-one".