Search a number
-
+
34021020151 is a prime number
BaseRepresentation
bin11111101011110011…
…111001000111110111
310020210222112220001101
4133223303321013313
51024133340121101
623343512310531
72313033620446
oct375363710767
9106728486041
1034021020151
1113478a84a88
1267156a2447
133292466371
14190a4b0d5d
15d41b52401
hex7ebcf91f7

34021020151 has 2 divisors, whose sum is σ = 34021020152. Its totient is φ = 34021020150.

The previous prime is 34021020149. The next prime is 34021020161. The reversal of 34021020151 is 15102012043.

It is a weak prime.

It is an emirp because it is prime and its reverse (15102012043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34021020151 - 21 = 34021020149 is a prime.

It is a super-2 number, since 2×340210201512 (a number of 22 digits) contains 22 as substring.

Together with 34021020149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34021020161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17010510075 + 17010510076.

It is an arithmetic number, because the mean of its divisors is an integer number (17010510076).

Almost surely, 234021020151 is an apocalyptic number.

34021020151 is a deficient number, since it is larger than the sum of its proper divisors (1).

34021020151 is an equidigital number, since it uses as much as digits as its factorization.

34021020151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 34021020151 its reverse (15102012043), we get a palindrome (49123032194).

The spelling of 34021020151 in words is "thirty-four billion, twenty-one million, twenty thousand, one hundred fifty-one".