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3402112010111 is a prime number
BaseRepresentation
bin110001100000011101101…
…011011000011101111111
3110001020110000221212122122
4301200131223120131333
5421220011133310421
611122524135233155
7500536335643013
oct61403553303577
913036400855578
103402112010111
1110a191159a581
1246b4285187bb
131b8a828a2869
14ba93d790543
155d76b7782ab
hex3181dad877f

3402112010111 has 2 divisors, whose sum is σ = 3402112010112. Its totient is φ = 3402112010110.

The previous prime is 3402112010053. The next prime is 3402112010117. The reversal of 3402112010111 is 1110102112043.

3402112010111 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3402112010111 is a prime.

It is a super-2 number, since 2×34021120101112 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3402112010111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3402112010117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1701056005055 + 1701056005056.

It is an arithmetic number, because the mean of its divisors is an integer number (1701056005056).

Almost surely, 23402112010111 is an apocalyptic number.

3402112010111 is a deficient number, since it is larger than the sum of its proper divisors (1).

3402112010111 is an equidigital number, since it uses as much as digits as its factorization.

3402112010111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 3402112010111 its reverse (1110102112043), we get a palindrome (4512214122154).

The spelling of 3402112010111 in words is "three trillion, four hundred two billion, one hundred twelve million, ten thousand, one hundred eleven".