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340241000011403 = 1720014176471259
BaseRepresentation
bin100110101011100101000011…
…1111100011001011010001011
31122121200201111021220122220212
41031113022013330121122023
5324044002032000331103
63203344320235111335
7131444413106040551
oct11527120774313213
91577621437818825
10340241000011403
1199458441495137
12321b0b9a5a254b
13117b07862b340a
146003a76311bd1
1529506b11bb7d8
hex1357287f1968b

340241000011403 has 4 divisors (see below), whose sum is σ = 360255176482680. Its totient is φ = 320226823540128.

The previous prime is 340241000011399. The next prime is 340241000011441. The reversal of 340241000011403 is 304110000142043.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 340241000011403 - 22 = 340241000011399 is a prime.

It is a super-2 number, since 2×3402410000114032 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (340241000014403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10007088235613 + ... + 10007088235646.

It is an arithmetic number, because the mean of its divisors is an integer number (90063794120670).

Almost surely, 2340241000011403 is an apocalyptic number.

340241000011403 is a deficient number, since it is larger than the sum of its proper divisors (20014176471277).

340241000011403 is a wasteful number, since it uses less digits than its factorization.

340241000011403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20014176471276.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 340241000011403 its reverse (304110000142043), we get a palindrome (644351000153446).

The spelling of 340241000011403 in words is "three hundred forty trillion, two hundred forty-one billion, eleven thousand, four hundred three".

Divisors: 1 17 20014176471259 340241000011403