Base | Representation |
---|---|
bin | 11111101100011011… |
… | …101011110001100011 |
3 | 10020211201011211210211 |
4 | 133230123223301203 |
5 | 1024144022414420 |
6 | 23344524034551 |
7 | 2313221363665 |
oct | 375433536143 |
9 | 106751154724 |
10 | 34031451235 |
11 | 1348395a011 |
12 | 6719092a57 |
13 | 32946791c2 |
14 | 190ba28535 |
15 | d42a12e5a |
hex | 7ec6ebc63 |
34031451235 has 4 divisors (see below), whose sum is σ = 40837741488. Its totient is φ = 27225160984.
The previous prime is 34031451197. The next prime is 34031451253. The reversal of 34031451235 is 53215413043.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53215413043 = 13 ⋅4093493311.
It is a cyclic number.
It is not a de Polignac number, because 34031451235 - 215 = 34031418467 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34031451197 and 34031451206.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3403145119 + ... + 3403145128.
It is an arithmetic number, because the mean of its divisors is an integer number (10209435372).
Almost surely, 234031451235 is an apocalyptic number.
34031451235 is a deficient number, since it is larger than the sum of its proper divisors (6806290253).
34031451235 is an equidigital number, since it uses as much as digits as its factorization.
34031451235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6806290252.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 34031451235 its reverse (53215413043), we get a palindrome (87246864278).
The spelling of 34031451235 in words is "thirty-four billion, thirty-one million, four hundred fifty-one thousand, two hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.092 sec. • engine limits •