34041320221 has 4 divisors (see below), whose sum is σ = 34136143200. Its totient is φ = 33946497244.

The previous prime is 34041320213. The next prime is 34041320237. The reversal of 34041320221 is 12202314043.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12202314043 = 17 ⋅717783179.

It is a cyclic number.

It is not a de Polignac number, because 34041320221 - 2³ = 34041320213 is a prime.

It is a super-2 number, since 2×34041320221² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34041320192 and 34041320201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34041320321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47410951 + ... + 47411668.

It is an arithmetic number, because the mean of its divisors is an integer number (8534035800).

Almost surely, 2^34041320221 is an apocalyptic number.

It is an amenable number.

34041320221 is a deficient number, since it is larger than the sum of its proper divisors (94822979).

34041320221 is an equidigital number, since it uses as much as digits as its factorization.

34041320221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94822978.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 34041320221 its reverse (12202314043), we get a palindrome (46243634264).

The spelling of 34041320221 in words is "thirty-four billion, forty-one million, three hundred twenty thousand, two hundred twenty-one".