Base | Representation |
---|---|
bin | 100110101100111001100011… |
… | …0001101100000110101101111 |
3 | 1122122100001210200200022002221 |
4 | 1031121303012031200311233 |
5 | 324104440120411441421 |
6 | 3204003523520300211 |
7 | 131463465150460123 |
oct | 11531630615406557 |
9 | 1578301720608087 |
10 | 340422433312111 |
11 | 995183858a0357 |
12 | 32220194171667 |
13 | 117c490bb65897 |
14 | 600c76860b583 |
15 | 295527e646841 |
hex | 1359cc6360d6f |
340422433312111 has 2 divisors, whose sum is σ = 340422433312112. Its totient is φ = 340422433312110.
The previous prime is 340422433312097. The next prime is 340422433312147. The reversal of 340422433312111 is 111213334224043.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 340422433312111 - 25 = 340422433312079 is a prime.
It is a super-2 number, since 2×3404224333121112 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340422431312111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170211216656055 + 170211216656056.
It is an arithmetic number, because the mean of its divisors is an integer number (170211216656056).
Almost surely, 2340422433312111 is an apocalyptic number.
340422433312111 is a deficient number, since it is larger than the sum of its proper divisors (1).
340422433312111 is an equidigital number, since it uses as much as digits as its factorization.
340422433312111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 340422433312111 its reverse (111213334224043), we get a palindrome (451635767536154).
The spelling of 340422433312111 in words is "three hundred forty trillion, four hundred twenty-two billion, four hundred thirty-three million, three hundred twelve thousand, one hundred eleven".
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