Base | Representation |
---|---|
bin | 1001111010000101110… |
… | …10101110000010001111 |
3 | 1012112200210220011102122 |
4 | 10331002322232002033 |
5 | 21034142311334201 |
6 | 420220015243155 |
7 | 33411023440046 |
oct | 4750272560217 |
9 | 1175623804378 |
10 | 340425105551 |
11 | 121412108443 |
12 | 55b878194bb |
13 | 26142ca29cb |
14 | 12695d6b55d |
15 | 8cc6667e1b |
hex | 4f42eae08f |
340425105551 has 2 divisors, whose sum is σ = 340425105552. Its totient is φ = 340425105550.
The previous prime is 340425105533. The next prime is 340425105569. The reversal of 340425105551 is 155501524043.
It is a balanced prime because it is at equal distance from previous prime (340425105533) and next prime (340425105569).
It is an emirp because it is prime and its reverse (155501524043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 340425105551 - 26 = 340425105487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340425105151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170212552775 + 170212552776.
It is an arithmetic number, because the mean of its divisors is an integer number (170212552776).
Almost surely, 2340425105551 is an apocalyptic number.
340425105551 is a deficient number, since it is larger than the sum of its proper divisors (1).
340425105551 is an equidigital number, since it uses as much as digits as its factorization.
340425105551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60000, while the sum is 35.
Adding to 340425105551 its reverse (155501524043), we get a palindrome (495926629594).
The spelling of 340425105551 in words is "three hundred forty billion, four hundred twenty-five million, one hundred five thousand, five hundred fifty-one".
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