Base | Representation |
---|---|
bin | 11111101101001100… |
… | …000110110111111111 |
3 | 10020212121001202120212 |
4 | 133231030012313333 |
5 | 1024210300121101 |
6 | 23350100103035 |
7 | 2313434313332 |
oct | 375514066777 |
9 | 106777052525 |
10 | 34044145151 |
11 | 1349003a155 |
12 | 6721394a7b |
13 | 32971a1cb3 |
14 | 190d5b0619 |
15 | d43bbe1bb |
hex | 7ed306dff |
34044145151 has 2 divisors, whose sum is σ = 34044145152. Its totient is φ = 34044145150.
The previous prime is 34044145139. The next prime is 34044145153. The reversal of 34044145151 is 15154144043.
It is a strong prime.
It is an emirp because it is prime and its reverse (15154144043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34044145151 - 26 = 34044145087 is a prime.
Together with 34044145153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34044145153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17022072575 + 17022072576.
It is an arithmetic number, because the mean of its divisors is an integer number (17022072576).
Almost surely, 234044145151 is an apocalyptic number.
34044145151 is a deficient number, since it is larger than the sum of its proper divisors (1).
34044145151 is an equidigital number, since it uses as much as digits as its factorization.
34044145151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 34044145151 its reverse (15154144043), we get a palindrome (49198289194).
The spelling of 34044145151 in words is "thirty-four billion, forty-four million, one hundred forty-five thousand, one hundred fifty-one".
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