Base | Representation |
---|---|
bin | 1001111010001110111… |
… | …01100100011011010111 |
3 | 1012112220010100210021221 |
4 | 10331013131210123113 |
5 | 21034321321200403 |
6 | 420231341351211 |
7 | 33412640502265 |
oct | 4750735443327 |
9 | 1175803323257 |
10 | 340501350103 |
11 | 121451154072 |
12 | 55ba9268507 |
13 | 26155a19925 |
14 | 126a2137435 |
15 | 8ccd1c8dbd |
hex | 4f477646d7 |
340501350103 has 2 divisors, whose sum is σ = 340501350104. Its totient is φ = 340501350102.
The previous prime is 340501350083. The next prime is 340501350169. The reversal of 340501350103 is 301053105043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 340501350103 - 25 = 340501350071 is a prime.
It is a super-2 number, since 2×3405013501032 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340501359103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170250675051 + 170250675052.
It is an arithmetic number, because the mean of its divisors is an integer number (170250675052).
Almost surely, 2340501350103 is an apocalyptic number.
340501350103 is a deficient number, since it is larger than the sum of its proper divisors (1).
340501350103 is an equidigital number, since it uses as much as digits as its factorization.
340501350103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 340501350103 its reverse (301053105043), we get a palindrome (641554455146).
The spelling of 340501350103 in words is "three hundred forty billion, five hundred one million, three hundred fifty thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •