Base | Representation |
---|---|
bin | 1100101101000001… |
… | …0001010011000001 |
3 | 22210122120222110211 |
4 | 3023100101103001 |
5 | 23440432240001 |
6 | 1322212554121 |
7 | 150334601404 |
oct | 31320212301 |
9 | 8718528424 |
10 | 3410040001 |
11 | 149a973585 |
12 | 7b2022941 |
13 | 42462c964 |
14 | 244c61d3b |
15 | 14e58c351 |
hex | cb4114c1 |
3410040001 has 2 divisors, whose sum is σ = 3410040002. Its totient is φ = 3410040000.
The previous prime is 3410039999. The next prime is 3410040017. The reversal of 3410040001 is 1000400143.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3378399376 + 31640625 = 58124^2 + 5625^2 .
It is an emirp because it is prime and its reverse (1000400143) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3410040001 - 21 = 3410039999 is a prime.
Together with 3410039999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3410040041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1705020000 + 1705020001.
It is an arithmetic number, because the mean of its divisors is an integer number (1705020001).
Almost surely, 23410040001 is an apocalyptic number.
It is an amenable number.
3410040001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3410040001 is an equidigital number, since it uses as much as digits as its factorization.
3410040001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 3410040001 is about 58395.5477840563. The cubic root of 3410040001 is about 1505.1732490776.
Adding to 3410040001 its reverse (1000400143), we get a palindrome (4410440144).
The spelling of 3410040001 in words is "three billion, four hundred ten million, forty thousand, one".
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