341022412130040 has 512 divisors, whose sum is σ = 1167808275072000. Its totient is φ = 88485965568000.

The previous prime is 341022412129957. The next prime is 341022412130189. The reversal of 341022412130040 is 40031214220143.

341022412130040 is a `hidden beast` number, since 3 + 4 + 10 + 224 + 121 + 300 + 4 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 341022412129986 and 341022412130013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 29739456387 + ... + 29739467853.

It is an arithmetic number, because the mean of its divisors is an integer number (2280875537250).

Almost surely, 2^{341022412130040} is an apocalyptic number.

341022412130040 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 341022412130040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (583904137536000).

341022412130040 is an abundant number, since it is smaller than the sum of its proper divisors (826785862941960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

341022412130040 is a wasteful number, since it uses less digits than its factorization.

341022412130040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16268 (or 16258 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 341022412130040 its reverse (40031214220143), we get a palindrome (381053626350183).

The spelling of 341022412130040 in words is "three hundred forty-one trillion, twenty-two billion, four hundred twelve million, one hundred thirty thousand, forty".