Base | Representation |
---|---|
bin | 110001101000110110100… |
… | …111011100001111111011 |
3 | 110002002200211201112212212 |
4 | 301220312213130033323 |
5 | 421341433301421021 |
6 | 11131014055125335 |
7 | 501305512335224 |
oct | 61506647341773 |
9 | 13062624645785 |
10 | 3411120342011 |
11 | 10a5714561678 |
12 | 47112137384b |
13 | 1b9889cac375 |
14 | bb155d3424b |
15 | 5dae754d85b |
hex | 31a369dc3fb |
3411120342011 has 2 divisors, whose sum is σ = 3411120342012. Its totient is φ = 3411120342010.
The previous prime is 3411120341999. The next prime is 3411120342023. The reversal of 3411120342011 is 1102430211143.
It is a balanced prime because it is at equal distance from previous prime (3411120341999) and next prime (3411120342023).
It is a cyclic number.
It is not a de Polignac number, because 3411120342011 - 26 = 3411120341947 is a prime.
It is a super-2 number, since 2×34111203420112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3411120342041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1705560171005 + 1705560171006.
It is an arithmetic number, because the mean of its divisors is an integer number (1705560171006).
Almost surely, 23411120342011 is an apocalyptic number.
3411120342011 is a deficient number, since it is larger than the sum of its proper divisors (1).
3411120342011 is an equidigital number, since it uses as much as digits as its factorization.
3411120342011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 3411120342011 its reverse (1102430211143), we get a palindrome (4513550553154).
The spelling of 3411120342011 in words is "three trillion, four hundred eleven billion, one hundred twenty million, three hundred forty-two thousand, eleven".
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