Base | Representation |
---|---|
bin | 1111100000110100100111… |
… | …10111110000010000000111 |
3 | 11110210011220100221021101201 |
4 | 13300122103313300100013 |
5 | 13432402122422144033 |
6 | 200315202533203331 |
7 | 10120406460221062 |
oct | 760322367602007 |
9 | 143704810837351 |
10 | 34113111131143 |
11 | a96231a9a76a0 |
12 | 39ab423a90547 |
13 | 1605b11159285 |
14 | 85d124b638d9 |
15 | 3e256107347d |
hex | 1f0693df0407 |
34113111131143 has 4 divisors (see below), whose sum is σ = 37214303052168. Its totient is φ = 31011919210120.
The previous prime is 34113111131131. The next prime is 34113111131191.
34113111131143 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34113111131143 - 217 = 34113111000071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34113111141143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1550595960496 + ... + 1550595960517.
It is an arithmetic number, because the mean of its divisors is an integer number (9303575763042).
Almost surely, 234113111131143 is an apocalyptic number.
34113111131143 is a deficient number, since it is larger than the sum of its proper divisors (3101191921025).
34113111131143 is a wasteful number, since it uses less digits than its factorization.
34113111131143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3101191921024.
The product of its digits is 1296, while the sum is 28.
It can be divided in two parts, 3411311 and 1131143, that added together give a palindrome (4542454).
The spelling of 34113111131143 in words is "thirty-four trillion, one hundred thirteen billion, one hundred eleven million, one hundred thirty-one thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.032 sec. • engine limits •