3411324133 has 4 divisors (see below), whose sum is σ = 3898656160. Its totient is φ = 2923992108.

The previous prime is 3411324131. The next prime is 3411324173. The reversal of 3411324133 is 3314231143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3314231143 = 421 ⋅7872283.

It is a cyclic number.

It is not a de Polignac number, because 3411324133 - 2¹ = 3411324131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3411324098 and 3411324107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3411324131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243666003 + ... + 243666016.

It is an arithmetic number, because the mean of its divisors is an integer number (974664040).

Almost surely, 2^3411324133 is an apocalyptic number.

It is an amenable number.

3411324133 is a deficient number, since it is larger than the sum of its proper divisors (487332027).

3411324133 is an equidigital number, since it uses as much as digits as its factorization.

3411324133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 487332026.

The product of its digits is 2592, while the sum is 25.

The square root of 3411324133 is about 58406.5418681846. The cubic root of 3411324133 is about 1505.3621616774.

Adding to 3411324133 its reverse (3314231143), we get a palindrome (6725555276).

The spelling of 3411324133 in words is "three billion, four hundred eleven million, three hundred twenty-four thousand, one hundred thirty-three".