341200210012001 has 2 divisors, whose sum is σ = 341200210012002. Its totient is φ = 341200210012000.

The previous prime is 341200210011989. The next prime is 341200210012003. The reversal of 341200210012001 is 100210012002143.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 307267243321600 + 33932966690401 = 17529040^2 + 5825201^2 .

It is an emirp because it is prime and its reverse (100210012002143) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-341200210012001 is a prime.

Together with 341200210012003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (341200210012003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170600105006000 + 170600105006001.

It is an arithmetic number, because the mean of its divisors is an integer number (170600105006001).

Almost surely, 2^{341200210012001} is an apocalyptic number.

It is an amenable number.

341200210012001 is a deficient number, since it is larger than the sum of its proper divisors (1).

341200210012001 is an equidigital number, since it uses as much as digits as its factorization.

341200210012001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 341200210012001 its reverse (100210012002143), we get a palindrome (441410222014144).

The spelling of 341200210012001 in words is "three hundred forty-one trillion, two hundred billion, two hundred ten million, twelve thousand, one".