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3412540531069 is a prime number
BaseRepresentation
bin110001101010001011010…
…001000010000101111101
3110002020100211001122000121
4301222023101002011331
5421402340333443234
611131411030454541
7501355635625135
oct61521321020575
913066324048017
103412540531069
1110a628318a73a
12471458b04451
131b9a552a9317
14bb24c7bdac5
155db7c0804b4
hex31a8b44217d

3412540531069 has 2 divisors, whose sum is σ = 3412540531070. Its totient is φ = 3412540531068.

The previous prime is 3412540531067. The next prime is 3412540531133. The reversal of 3412540531069 is 9601350452143.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2555873664100 + 856666866969 = 1598710^2 + 925563^2 .

It is a cyclic number.

It is not a de Polignac number, because 3412540531069 - 21 = 3412540531067 is a prime.

It is a super-2 number, since 2×34125405310692 (a number of 26 digits) contains 22 as substring.

Together with 3412540531067, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3412540531063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706270265534 + 1706270265535.

It is an arithmetic number, because the mean of its divisors is an integer number (1706270265535).

Almost surely, 23412540531069 is an apocalyptic number.

It is an amenable number.

3412540531069 is a deficient number, since it is larger than the sum of its proper divisors (1).

3412540531069 is an equidigital number, since it uses as much as digits as its factorization.

3412540531069 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 43.

The spelling of 3412540531069 in words is "three trillion, four hundred twelve billion, five hundred forty million, five hundred thirty-one thousand, sixty-nine".