34130444403143 has 4 divisors (see below), whose sum is σ = 37233212076168. Its totient is φ = 31027676730120.

The previous prime is 34130444403079. The next prime is 34130444403197.

34130444403143 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34130444403143 - 2⁶ = 34130444403079 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34130444403097 and 34130444403106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34130444403743) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1551383836496 + ... + 1551383836517.

It is an arithmetic number, because the mean of its divisors is an integer number (9308303019042).

Almost surely, 2^{34130444403143} is an apocalyptic number.

34130444403143 is a deficient number, since it is larger than the sum of its proper divisors (3102767673025).

34130444403143 is a wasteful number, since it uses less digits than its factorization.

34130444403143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3102767673024.

The product of its (nonzero) digits is 331776, while the sum is 38.

It can be divided in two parts, 3413044 and 4403143, that added together give a palindrome (7816187).

The spelling of 34130444403143 in words is "thirty-four trillion, one hundred thirty billion, four hundred forty-four million, four hundred three thousand, one hundred forty-three".