Base | Representation |
---|---|
bin | 110001101010101101111… |
… | …000111000010100011111 |
3 | 110002021212022001221100002 |
4 | 301222231320320110133 |
5 | 421410033034332033 |
6 | 11131544420524515 |
7 | 501406221143615 |
oct | 61525570702437 |
9 | 13067768057302 |
10 | 3413121402143 |
11 | 10a6551062782 |
12 | 47159b55073b |
13 | 1b9b1873810b |
14 | bb2a59c76b5 |
15 | 5dbb30703e8 |
hex | 31aade3851f |
3413121402143 has 2 divisors, whose sum is σ = 3413121402144. Its totient is φ = 3413121402142.
The previous prime is 3413121402017. The next prime is 3413121402161. The reversal of 3413121402143 is 3412041213143.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3413121402143 - 218 = 3413121139999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3413121402343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1706560701071 + 1706560701072.
It is an arithmetic number, because the mean of its divisors is an integer number (1706560701072).
Almost surely, 23413121402143 is an apocalyptic number.
3413121402143 is a deficient number, since it is larger than the sum of its proper divisors (1).
3413121402143 is an equidigital number, since it uses as much as digits as its factorization.
3413121402143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 3413121402143 its reverse (3412041213143), we get a palindrome (6825162615286).
The spelling of 3413121402143 in words is "three trillion, four hundred thirteen billion, one hundred twenty-one million, four hundred two thousand, one hundred forty-three".
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