34131333313143 has 48 divisors (see below), whose sum is σ = 55528296026112. Its totient is φ = 20022221520000.

The previous prime is 34131333313127. The next prime is 34131333313213.

34131333313143 is a `hidden beast` number, since 3 + 4 + 1 + 3 + 1 + 3 + 3 + 331 + 314 + 3 = 666.

34131333313143 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 34131333313143 - 2⁴ = 34131333313127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34131333313098 and 34131333313107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (34131333303143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 32590033 + ... + 33621018.

It is an arithmetic number, because the mean of its divisors is an integer number (1156839500544).

Almost surely, 2^{34131333313143} is an apocalyptic number.

34131333313143 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

34131333313143 is a deficient number, since it is larger than the sum of its proper divisors (21396962712969).

34131333313143 is a wasteful number, since it uses less digits than its factorization.

34131333313143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66211236 (or 66211233 counting only the distinct ones).

The product of its digits is 104976, while the sum is 36.

It can be divided in two parts, 3413133 and 3313143, that added together give a palindrome (6726276).

The spelling of 34131333313143 in words is "thirty-four trillion, one hundred thirty-one billion, three hundred thirty-three million, three hundred thirteen thousand, one hundred forty-three".