Base | Representation |
---|---|
bin | 1111100001011000001101… |
… | …01001100010101010100101 |
3 | 11110212000012212100102100221 |
4 | 13300230012221202222211 |
5 | 13433210234430421001 |
6 | 200332042431004341 |
7 | 10121654101412260 |
oct | 760540651425245 |
9 | 143760185312327 |
10 | 34132216654501 |
11 | a96a434527119 |
12 | 39b30763696b1 |
13 | 1607867422594 |
14 | 860018329cd7 |
15 | 3e2ccd5041a1 |
hex | 1f0b06a62aa5 |
34132216654501 has 4 divisors (see below), whose sum is σ = 39008247605152. Its totient is φ = 29256185703852.
The previous prime is 34132216654477. The next prime is 34132216654511. The reversal of 34132216654501 is 10545661223143.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 34132216654501 - 27 = 34132216654373 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34132216654511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2438015475315 + ... + 2438015475328.
It is an arithmetic number, because the mean of its divisors is an integer number (9752061901288).
Almost surely, 234132216654501 is an apocalyptic number.
It is an amenable number.
34132216654501 is a deficient number, since it is larger than the sum of its proper divisors (4876030950651).
34132216654501 is an equidigital number, since it uses as much as digits as its factorization.
34132216654501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4876030950650.
The product of its (nonzero) digits is 518400, while the sum is 43.
Adding to 34132216654501 its reverse (10545661223143), we get a palindrome (44677877877644).
The spelling of 34132216654501 in words is "thirty-four trillion, one hundred thirty-two billion, two hundred sixteen million, six hundred fifty-four thousand, five hundred one".
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