Base | Representation |
---|---|
bin | 110001101010111011001… |
… | …011101011001111110111 |
3 | 110002022102211202002100111 |
4 | 301222323023223033313 |
5 | 421411012133330033 |
6 | 11132022505123451 |
7 | 501414566653021 |
oct | 61527313531767 |
9 | 13068384662314 |
10 | 3413344433143 |
11 | 10a6655a46217 |
12 | 471642189587 |
13 | 1b9b529c7318 |
14 | bb2c7483011 |
15 | 5dbc79287cd |
hex | 31abb2eb3f7 |
3413344433143 has 16 divisors (see below), whose sum is σ = 3474803502720. Its totient is φ = 3352007340000.
The previous prime is 3413344433129. The next prime is 3413344433153.
3413344433143 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 3413344433143 - 225 = 3413310878711 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3413344433096 and 3413344433105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3413344433153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 344742493 + ... + 344752393.
It is an arithmetic number, because the mean of its divisors is an integer number (217175218920).
Almost surely, 23413344433143 is an apocalyptic number.
3413344433143 is a deficient number, since it is larger than the sum of its proper divisors (61459069577).
3413344433143 is a wasteful number, since it uses less digits than its factorization.
3413344433143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15438.
The product of its digits is 746496, while the sum is 40.
The spelling of 3413344433143 in words is "three trillion, four hundred thirteen billion, three hundred forty-four million, four hundred thirty-three thousand, one hundred forty-three".
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