3414104244841 has 2 divisors, whose sum is σ = 3414104244842. Its totient is φ = 3414104244840.

The previous prime is 3414104244829. The next prime is 3414104244853. The reversal of 3414104244841 is 1484424014143.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (3414104244829) and next prime (3414104244853).

It can be written as a sum of positive squares in only one way, i.e., 3385246729216 + 28857515625 = 1839904^2 + 169875^2 .

It is a cyclic number.

It is not a de Polignac number, because 3414104244841 - 2¹⁵ = 3414104212073 is a prime.

It is a super-2 number, since 2×3414104244841² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3414104244794 and 3414104244803.

It is not a weakly prime, because it can be changed into another prime (3414104242841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1707052122420 + 1707052122421.

It is an arithmetic number, because the mean of its divisors is an integer number (1707052122421).

Almost surely, 2^{3414104244841} is an apocalyptic number.

It is an amenable number.

3414104244841 is a deficient number, since it is larger than the sum of its proper divisors (1).

3414104244841 is an equidigital number, since it uses as much as digits as its factorization.

3414104244841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 196608, while the sum is 40.

Adding to 3414104244841 its reverse (1484424014143), we get a palindrome (4898528258984).

The spelling of 3414104244841 in words is "three trillion, four hundred fourteen billion, one hundred four million, two hundred forty-four thousand, eight hundred forty-one".