Base | Representation |
---|---|
bin | 110001110001000011010… |
… | …111110111110110000111 |
3 | 110002221102101220220122020 |
4 | 301301003113313312013 |
5 | 422013001110033033 |
6 | 11135031434334223 |
7 | 502036624622562 |
oct | 61610327676607 |
9 | 13087371826566 |
10 | 3419924299143 |
11 | 10a9422122a00 |
12 | 47297988a373 |
13 | 1ba660c5c561 |
14 | bb74d2b74d9 |
15 | 5de604036b3 |
hex | 31c435f7d87 |
3419924299143 has 24 divisors (see below), whose sum is σ = 5013259599600. Its totient is φ = 2072210321280.
The previous prime is 3419924299087. The next prime is 3419924299151.
3419924299143 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3419924299143 - 28 = 3419924298887 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3419924299943) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 532053 + ... + 2668881.
It is an arithmetic number, because the mean of its divisors is an integer number (208885816650).
Almost surely, 23419924299143 is an apocalyptic number.
3419924299143 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3419924299143 is a deficient number, since it is larger than the sum of its proper divisors (1593335300457).
3419924299143 is a wasteful number, since it uses less digits than its factorization.
3419924299143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2141263 (or 2141252 counting only the distinct ones).
The product of its digits is 15116544, while the sum is 60.
It can be divided in two parts, 34199 and 24299143, that added together give a palindrome (24333342).
The spelling of 3419924299143 in words is "three trillion, four hundred nineteen billion, nine hundred twenty-four million, two hundred ninety-nine thousand, one hundred forty-three".
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