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3420111412121 is a prime number
BaseRepresentation
bin110001110001001110100…
…001101001101110011001
3110002221220110000020101112
4301301032201221232121
5422013342010141441
611135102201030105
7502044356224505
oct61611641515631
913087813006345
103420111412121
1110a9508803728
12472a10485335
131ba690953bb1
14bb76a0a3305
155de71a644eb
hex31c4e869b99

3420111412121 has 2 divisors, whose sum is σ = 3420111412122. Its totient is φ = 3420111412120.

The previous prime is 3420111412111. The next prime is 3420111412177. The reversal of 3420111412121 is 1212141110243.

3420111412121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2918083897600 + 502027514521 = 1708240^2 + 708539^2 .

It is a cyclic number.

It is not a de Polignac number, because 3420111412121 - 218 = 3420111149977 is a prime.

It is not a weakly prime, because it can be changed into another prime (3420111412111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710055706060 + 1710055706061.

It is an arithmetic number, because the mean of its divisors is an integer number (1710055706061).

Almost surely, 23420111412121 is an apocalyptic number.

It is an amenable number.

3420111412121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3420111412121 is an equidigital number, since it uses as much as digits as its factorization.

3420111412121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 3420111412121 its reverse (1212141110243), we get a palindrome (4632252522364).

The spelling of 3420111412121 in words is "three trillion, four hundred twenty billion, one hundred eleven million, four hundred twelve thousand, one hundred twenty-one".