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34201121242199 is a prime number
BaseRepresentation
bin1111100011011000100011…
…01011101011110001010111
311111002121001221111011001112
413301230101223223301113
513440322344014222244
6200423440031245235
710126643444634122
oct761542153536127
9144077057434045
1034201121242199
11a99668335776a
123a044a637981b
1316111c8934472
148634b36793b9
153e49b288839e
hex1f1b11aebc57

34201121242199 has 2 divisors, whose sum is σ = 34201121242200. Its totient is φ = 34201121242198.

The previous prime is 34201121242163. The next prime is 34201121242201. The reversal of 34201121242199 is 99124212110243.

It is a strong prime.

It is an emirp because it is prime and its reverse (99124212110243) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34201121242199 is a prime.

Together with 34201121242201, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34201121242109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17100560621099 + 17100560621100.

It is an arithmetic number, because the mean of its divisors is an integer number (17100560621100).

Almost surely, 234201121242199 is an apocalyptic number.

34201121242199 is a deficient number, since it is larger than the sum of its proper divisors (1).

34201121242199 is an equidigital number, since it uses as much as digits as its factorization.

34201121242199 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 41.

The spelling of 34201121242199 in words is "thirty-four trillion, two hundred one billion, one hundred twenty-one million, two hundred forty-two thousand, one hundred ninety-nine".