Base | Representation |
---|---|
bin | 110001110001001111000… |
… | …010111010011101111111 |
3 | 110002221221001102020001211 |
4 | 301301033002322131333 |
5 | 422013401223201310 |
6 | 11135103111545251 |
7 | 502044523311346 |
oct | 61611702723577 |
9 | 13087831366054 |
10 | 3420120131455 |
11 | 10a9512719695 |
12 | 472a1338b227 |
13 | 1ba6926b7871 |
14 | bb76b2d2b5d |
15 | 5de726d7c8a |
hex | 31c4f0ba77f |
3420120131455 has 4 divisors (see below), whose sum is σ = 4104144157752. Its totient is φ = 2736096105160.
The previous prime is 3420120131437. The next prime is 3420120131531. The reversal of 3420120131455 is 5541310210243.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 3420120131455 - 25 = 3420120131423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342012013141 + ... + 342012013150.
It is an arithmetic number, because the mean of its divisors is an integer number (1026036039438).
Almost surely, 23420120131455 is an apocalyptic number.
3420120131455 is a deficient number, since it is larger than the sum of its proper divisors (684024026297).
3420120131455 is an equidigital number, since it uses as much as digits as its factorization.
3420120131455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 684024026296.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 3420120131455 its reverse (5541310210243), we get a palindrome (8961430341698).
The spelling of 3420120131455 in words is "three trillion, four hundred twenty billion, one hundred twenty million, one hundred thirty-one thousand, four hundred fifty-five".
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