Base | Representation |
---|---|
bin | 1001111101001101111… |
… | …00100001100000011101 |
3 | 1012201000202201021121020 |
4 | 10332212330201200131 |
5 | 21101111421101000 |
6 | 421054324554353 |
7 | 33500432033436 |
oct | 4764674414035 |
9 | 1181022637536 |
10 | 342103300125 |
11 | 1220a3437904 |
12 | 563758529b9 |
13 | 2634c886152 |
14 | 127b4bb848d |
15 | 8d73b60ba0 |
hex | 4fa6f2181d |
342103300125 has 32 divisors (see below), whose sum is σ = 569346710400. Its totient is φ = 182427267200.
The previous prime is 342103300117. The next prime is 342103300153. The reversal of 342103300125 is 521003301243.
342103300125 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 342103300125 - 23 = 342103300117 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 342103300095 and 342103300104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2521009 + ... + 2653241.
It is an arithmetic number, because the mean of its divisors is an integer number (17792084700).
Almost surely, 2342103300125 is an apocalyptic number.
It is an amenable number.
342103300125 is a deficient number, since it is larger than the sum of its proper divisors (227243410275).
342103300125 is a wasteful number, since it uses less digits than its factorization.
342103300125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139150 (or 139140 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 342103300125 its reverse (521003301243), we get a palindrome (863106601368).
The spelling of 342103300125 in words is "three hundred forty-two billion, one hundred three million, three hundred thousand, one hundred twenty-five".
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