342210113 has 4 divisors (see below), whose sum is σ = 391097280. Its totient is φ = 293322948.

The previous prime is 342210101. The next prime is 342210161. The reversal of 342210113 is 311012243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311012243 = 31 ⋅10032653.

It is a cyclic number.

It is not a de Polignac number, because 342210113 - 2⁴ = 342210097 is a prime.

It is a super-2 number, since 2×342210113² = 234215522878945538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 342210091 and 342210100.

It is not an unprimeable number, because it can be changed into a prime (342210163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24443573 + ... + 24443586.

It is an arithmetic number, because the mean of its divisors is an integer number (97774320).

Almost surely, 2^342210113 is an apocalyptic number.

It is an amenable number.

342210113 is a deficient number, since it is larger than the sum of its proper divisors (48887167).

342210113 is an equidigital number, since it uses as much as digits as its factorization.

342210113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48887166.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 342210113 is about 18498.9219415619. The cubic root of 342210113 is about 699.4622489016.

Adding to 342210113 its reverse (311012243), we get a palindrome (653222356).

The spelling of 342210113 in words is "three hundred forty-two million, two hundred ten thousand, one hundred thirteen".