Base | Representation |
---|---|
bin | 110001110110000000100… |
… | …110110111111000010111 |
3 | 110010110011022210021002112 |
4 | 301312000212313320113 |
5 | 422104401112441134 |
6 | 11141311522101235 |
7 | 502315542535652 |
oct | 61660046677027 |
9 | 13113138707075 |
10 | 3425246608919 |
11 | 1100703462023 |
12 | 473a041aa81b |
13 | 1baccb7ca795 |
14 | bbad60b8899 |
15 | 5e1727c41ce |
hex | 31d809b7e17 |
3425246608919 has 2 divisors, whose sum is σ = 3425246608920. Its totient is φ = 3425246608918.
The previous prime is 3425246608873. The next prime is 3425246608921. The reversal of 3425246608919 is 9198066425243.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3425246608919 - 236 = 3356527132183 is a prime.
It is a super-2 number, since 2×34252466089192 (a number of 26 digits) contains 22 as substring.
Together with 3425246608921, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3425246608019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1712623304459 + 1712623304460.
It is an arithmetic number, because the mean of its divisors is an integer number (1712623304460).
Almost surely, 23425246608919 is an apocalyptic number.
3425246608919 is a deficient number, since it is larger than the sum of its proper divisors (1).
3425246608919 is an equidigital number, since it uses as much as digits as its factorization.
3425246608919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22394880, while the sum is 59.
The spelling of 3425246608919 in words is "three trillion, four hundred twenty-five billion, two hundred forty-six million, six hundred eight thousand, nine hundred nineteen".
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