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34265117 is a prime number
BaseRepresentation
bin1000001010110…
…1100000011101
32101110211220102
42002231200131
532232440432
63222230445
7564151205
oct202554035
971424812
1034265117
1118383987
12b585425
137139423
14479d405
15301c962
hex20ad81d

34265117 has 2 divisors, whose sum is σ = 34265118. Its totient is φ = 34265116.

The previous prime is 34265087. The next prime is 34265123. The reversal of 34265117 is 71156243.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34175716 + 89401 = 5846^2 + 299^2 .

It is an emirp because it is prime and its reverse (71156243) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34265117 - 210 = 34264093 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34265117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34265167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17132558 + 17132559.

It is an arithmetic number, because the mean of its divisors is an integer number (17132559).

Almost surely, 234265117 is an apocalyptic number.

It is an amenable number.

34265117 is a deficient number, since it is larger than the sum of its proper divisors (1).

34265117 is an equidigital number, since it uses as much as digits as its factorization.

34265117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 29.

The square root of 34265117 is about 5853.6413453508. The cubic root of 34265117 is about 324.8010364056.

The spelling of 34265117 in words is "thirty-four million, two hundred sixty-five thousand, one hundred seventeen".