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343134134433173 is a prime number
BaseRepresentation
bin100111000000101000010010…
…0001100010111010110010101
31122222221022011210202002100002
41032001100210030113112111
5324433402201403330143
63213441351210301045
7132163423504625246
oct11601204414272625
91588838153662302
10343134134433173
119a373407443216
123259983b427785
1311960543b03c55
1460a3ad041cccd
1529a0a8dab05b8
hex1381424317595

343134134433173 has 2 divisors, whose sum is σ = 343134134433174. Its totient is φ = 343134134433172.

The previous prime is 343134134433143. The next prime is 343134134433203. The reversal of 343134134433173 is 371334431431343.

It is a balanced prime because it is at equal distance from previous prime (343134134433143) and next prime (343134134433203).

It can be written as a sum of positive squares in only one way, i.e., 336648259992529 + 6485874440644 = 18347977^2 + 2546738^2 .

It is a cyclic number.

It is not a de Polignac number, because 343134134433173 - 212 = 343134134429077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (343134134433143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171567067216586 + 171567067216587.

It is an arithmetic number, because the mean of its divisors is an integer number (171567067216587).

Almost surely, 2343134134433173 is an apocalyptic number.

It is an amenable number.

343134134433173 is a deficient number, since it is larger than the sum of its proper divisors (1).

343134134433173 is an equidigital number, since it uses as much as digits as its factorization.

343134134433173 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3919104, while the sum is 47.

The spelling of 343134134433173 in words is "three hundred forty-three trillion, one hundred thirty-four billion, one hundred thirty-four million, four hundred thirty-three thousand, one hundred seventy-three".