Search a number
-
+
343200142121 is a prime number
BaseRepresentation
bin1001111111010000101…
…00101001001100101001
31012210212012121121221212
410333220110221030221
521110333214021441
6421355230042505
733536551034504
oct4775024511451
91183765547855
10343200142121
111226065954a1
1256621049435
1326495b9c595
141287a73413b
158dda0c0eeb
hex4fe8529329

343200142121 has 2 divisors, whose sum is σ = 343200142122. Its totient is φ = 343200142120.

The previous prime is 343200141997. The next prime is 343200142123. The reversal of 343200142121 is 121241002343.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 188113038400 + 155087103721 = 433720^2 + 393811^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-343200142121 is a prime.

Together with 343200142123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (343200142123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171600071060 + 171600071061.

It is an arithmetic number, because the mean of its divisors is an integer number (171600071061).

Almost surely, 2343200142121 is an apocalyptic number.

It is an amenable number.

343200142121 is a deficient number, since it is larger than the sum of its proper divisors (1).

343200142121 is an equidigital number, since it uses as much as digits as its factorization.

343200142121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 343200142121 its reverse (121241002343), we get a palindrome (464441144464).

The spelling of 343200142121 in words is "three hundred forty-three billion, two hundred million, one hundred forty-two thousand, one hundred twenty-one".