Base | Representation |
---|---|
bin | 1111100110111101101100… |
… | …10011111100010010001111 |
3 | 11111112100121111101121011202 |
4 | 13303132312103330102033 |
5 | 13444331320414441221 |
6 | 201000143204340115 |
7 | 10141560150015362 |
oct | 763366623742217 |
9 | 144470544347152 |
10 | 34324142343311 |
11 | aa33872584867 |
12 | 3a242b99a463b |
13 | 161c9a29b0712 |
14 | 869423d1c0d9 |
15 | 3e7cb2b9ed0b |
hex | 1f37b64fc48f |
34324142343311 has 2 divisors, whose sum is σ = 34324142343312. Its totient is φ = 34324142343310.
The previous prime is 34324142343269. The next prime is 34324142343313. The reversal of 34324142343311 is 11334324142343.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34324142343311 - 242 = 29926095832207 is a prime.
Together with 34324142343313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34324142343313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17162071171655 + 17162071171656.
It is an arithmetic number, because the mean of its divisors is an integer number (17162071171656).
Almost surely, 234324142343311 is an apocalyptic number.
34324142343311 is a deficient number, since it is larger than the sum of its proper divisors (1).
34324142343311 is an equidigital number, since it uses as much as digits as its factorization.
34324142343311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 248832, while the sum is 38.
Adding to 34324142343311 its reverse (11334324142343), we get a palindrome (45658466485654).
The spelling of 34324142343311 in words is "thirty-four trillion, three hundred twenty-four billion, one hundred forty-two million, three hundred forty-three thousand, three hundred eleven".
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