34331005151 has 2 divisors, whose sum is σ = 34331005152. Its totient is φ = 34331005150.

The previous prime is 34331005123. The next prime is 34331005153. The reversal of 34331005151 is 15150013343.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-34331005151 is a prime.

It is a Sophie Germain prime.

Together with 34331005153, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34331005151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34331005153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17165502575 + 17165502576.

It is an arithmetic number, because the mean of its divisors is an integer number (17165502576).

Almost surely, 2^34331005151 is an apocalyptic number.

34331005151 is a deficient number, since it is larger than the sum of its proper divisors (1).

34331005151 is an equidigital number, since it uses as much as digits as its factorization.

34331005151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 34331005151 its reverse (15150013343), we get a palindrome (49481018494).

The spelling of 34331005151 in words is "thirty-four billion, three hundred thirty-one million, five thousand, one hundred fifty-one".