Base | Representation |
---|---|
bin | 11111111110010011… |
… | …010000101101111111 |
3 | 10021121121021100021202 |
4 | 133332103100231333 |
5 | 1030302243430101 |
6 | 23434353250115 |
7 | 2323521444515 |
oct | 377623205577 |
9 | 107547240252 |
10 | 34331233151 |
11 | 136180a4666 |
12 | 67a156393b |
13 | 33117cb957 |
14 | 19397824b5 |
15 | d5decc36b |
hex | 7fe4d0b7f |
34331233151 has 4 divisors (see below), whose sum is σ = 36350717472. Its totient is φ = 32311748832.
The previous prime is 34331233127. The next prime is 34331233159. The reversal of 34331233151 is 15133213343.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15133213343 = 58153 ⋅260231.
It is a cyclic number.
It is not a de Polignac number, because 34331233151 - 218 = 34330971007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34331233159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1009742135 + ... + 1009742168.
It is an arithmetic number, because the mean of its divisors is an integer number (9087679368).
Almost surely, 234331233151 is an apocalyptic number.
34331233151 is a deficient number, since it is larger than the sum of its proper divisors (2019484321).
34331233151 is a wasteful number, since it uses less digits than its factorization.
34331233151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2019484320.
The product of its digits is 9720, while the sum is 29.
Adding to 34331233151 its reverse (15133213343), we get a palindrome (49464446494).
The spelling of 34331233151 in words is "thirty-four billion, three hundred thirty-one million, two hundred thirty-three thousand, one hundred fifty-one".
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