Base | Representation |
---|---|
bin | 1111100111010000001001… |
… | …11011001110110000101000 |
3 | 11111120022012001122200020102 |
4 | 13303220010323032300220 |
5 | 14000012114101400130 |
6 | 201004502333444532 |
7 | 10142360536633454 |
oct | 763500473166050 |
9 | 144508161580212 |
10 | 34334051200040 |
11 | aa37a978a7559 |
12 | 3a26204340748 |
13 | 16208c1838757 |
14 | 869ac3d17664 |
15 | 3e8192a57645 |
hex | 1f3a04ecec28 |
34334051200040 has 32 divisors (see below), whose sum is σ = 77336787955680. Its totient is φ = 13718478656832.
The previous prime is 34334051200037. The next prime is 34334051200129. The reversal of 34334051200040 is 4000215043343.
It is a junction number, because it is equal to n+sod(n) for n = 34334051199976 and 34334051200012.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 473145242 + ... + 473217801.
It is an arithmetic number, because the mean of its divisors is an integer number (2416774623615).
Almost surely, 234334051200040 is an apocalyptic number.
It is an amenable number.
34334051200040 is an abundant number, since it is smaller than the sum of its proper divisors (43002736755640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
34334051200040 is a wasteful number, since it uses less digits than its factorization.
34334051200040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 946363961 (or 946363957 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 34334051200040 its reverse (4000215043343), we get a palindrome (38334266243383).
The spelling of 34334051200040 in words is "thirty-four trillion, three hundred thirty-four billion, fifty-one million, two hundred thousand, forty".
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