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3433677312493 is a prime number
BaseRepresentation
bin110001111101110111000…
…111011101000111101101
3110011020220212122101020001
4301331313013131013231
5422224132342444433
611145224245224301
7503034503406451
oct61756707350755
913136825571201
103433677312493
11110423a36643a
12475577702091
131bba4334248c
14bc295a5a661
155e4b79ea57d
hex31f771dd1ed

3433677312493 has 2 divisors, whose sum is σ = 3433677312494. Its totient is φ = 3433677312492.

The previous prime is 3433677312491. The next prime is 3433677312517. The reversal of 3433677312493 is 3942137763343.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2533231941769 + 900445370724 = 1591613^2 + 948918^2 .

It is a cyclic number.

It is not a de Polignac number, because 3433677312493 - 21 = 3433677312491 is a prime.

Together with 3433677312491, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3433677312491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1716838656246 + 1716838656247.

It is an arithmetic number, because the mean of its divisors is an integer number (1716838656247).

Almost surely, 23433677312493 is an apocalyptic number.

It is an amenable number.

3433677312493 is a deficient number, since it is larger than the sum of its proper divisors (1).

3433677312493 is an equidigital number, since it uses as much as digits as its factorization.

3433677312493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20575296, while the sum is 55.

The spelling of 3433677312493 in words is "three trillion, four hundred thirty-three billion, six hundred seventy-seven million, three hundred twelve thousand, four hundred ninety-three".