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34341140131 = 173319816007
BaseRepresentation
bin11111111110111001…
…000011011010100011
310021122021220200002221
4133332321003122203
51030312312441011
623435345451511
72324001606034
oct377671033243
9107567820087
1034341140131
1113622750951
1267a4940b97
13331388a07c
14193ac00a8b
15d5ecd7971
hex7fee436a3

34341140131 has 4 divisors (see below), whose sum is σ = 34360957872. Its totient is φ = 34321322392.

The previous prime is 34341140117. The next prime is 34341140149. The reversal of 34341140131 is 13104114343.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34341140131 - 221 = 34339042979 is a prime.

It is a super-2 number, since 2×343411401312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34341140096 and 34341140105.

It is not an unprimeable number, because it can be changed into a prime (34341140161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9906271 + ... + 9909736.

It is an arithmetic number, because the mean of its divisors is an integer number (8590239468).

Almost surely, 234341140131 is an apocalyptic number.

34341140131 is a deficient number, since it is larger than the sum of its proper divisors (19817741).

34341140131 is a wasteful number, since it uses less digits than its factorization.

34341140131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19817740.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 34341140131 its reverse (13104114343), we get a palindrome (47445254474).

The spelling of 34341140131 in words is "thirty-four billion, three hundred forty-one million, one hundred forty thousand, one hundred thirty-one".

Divisors: 1 1733 19816007 34341140131