Base | Representation |
---|---|
bin | 110001111110100010001… |
… | …100110010111110110100 |
3 | 110011022210020202110121120 |
4 | 301332202030302332310 |
5 | 422232122413224134 |
6 | 11145424105543540 |
7 | 503061431315136 |
oct | 61764214627664 |
9 | 13138706673546 |
10 | 3434400133044 |
11 | 11045803821a1 |
12 | 4757397a4bb0 |
13 | 1bbb2a011a4a |
14 | bc323a55056 |
15 | 5e50b1c9649 |
hex | 31fa2332fb4 |
3434400133044 has 24 divisors (see below), whose sum is σ = 8017447512480. Its totient is φ = 1144250444064.
The previous prime is 3434400133037. The next prime is 3434400133067. The reversal of 3434400133044 is 4403310044343.
It is a junction number, because it is equal to n+sod(n) for n = 3434400132996 and 3434400133014.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68673999 + ... + 68723990.
It is an arithmetic number, because the mean of its divisors is an integer number (334060313020).
Almost surely, 23434400133044 is an apocalyptic number.
It is an amenable number.
3434400133044 is an abundant number, since it is smaller than the sum of its proper divisors (4583047379436).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3434400133044 is a wasteful number, since it uses less digits than its factorization.
3434400133044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 137400079 (or 137400077 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 3434400133044 its reverse (4403310044343), we get a palindrome (7837710177387).
The spelling of 3434400133044 in words is "three trillion, four hundred thirty-four billion, four hundred million, one hundred thirty-three thousand, forty-four".
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