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3438840525119 is a prime number
BaseRepresentation
bin110010000010101010110…
…111100011000100111111
3110011202020201010202102022
4302002222313203010333
5422320221133300434
611151440450550355
7503306450113466
oct62025267430477
913152221122368
103438840525119
11110644990a50a
124765788983bb
131bc386c47b8c
14bc6256859dd
155e6bae4122e
hex320aade313f

3438840525119 has 2 divisors, whose sum is σ = 3438840525120. Its totient is φ = 3438840525118.

The previous prime is 3438840525083. The next prime is 3438840525121. The reversal of 3438840525119 is 9115250488343.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3438840525119 is a prime.

It is a super-2 number, since 2×34388405251192 (a number of 26 digits) contains 22 as substring.

Together with 3438840525121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3438840525019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1719420262559 + 1719420262560.

It is an arithmetic number, because the mean of its divisors is an integer number (1719420262560).

Almost surely, 23438840525119 is an apocalyptic number.

3438840525119 is a deficient number, since it is larger than the sum of its proper divisors (1).

3438840525119 is an equidigital number, since it uses as much as digits as its factorization.

3438840525119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4147200, while the sum is 53.

The spelling of 3438840525119 in words is "three trillion, four hundred thirty-eight billion, eight hundred forty million, five hundred twenty-five thousand, one hundred nineteen".