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34401000313 is a prime number
BaseRepresentation
bin100000000010011101…
…011001101101111001
310021210110112212211201
4200002131121231321
51030423124002223
623445324454201
72325326451361
oct400235315571
9107713485751
1034401000313
1113653516779
1268009aa361
1333230b84b4
141944b439a1
15d651adead
hex802759b79

34401000313 has 2 divisors, whose sum is σ = 34401000314. Its totient is φ = 34401000312.

The previous prime is 34401000311. The next prime is 34401000323. The reversal of 34401000313 is 31300010443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28683825769 + 5717174544 = 169363^2 + 75612^2 .

It is a cyclic number.

It is not a de Polignac number, because 34401000313 - 21 = 34401000311 is a prime.

Together with 34401000311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (34401000311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17200500156 + 17200500157.

It is an arithmetic number, because the mean of its divisors is an integer number (17200500157).

Almost surely, 234401000313 is an apocalyptic number.

It is an amenable number.

34401000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

34401000313 is an equidigital number, since it uses as much as digits as its factorization.

34401000313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 34401000313 its reverse (31300010443), we get a palindrome (65701010756).

The spelling of 34401000313 in words is "thirty-four billion, four hundred one million, three hundred thirteen", and thus it is an aban number.