3440124133 has 2 divisors, whose sum is σ = 3440124134. Its totient is φ = 3440124132.

The previous prime is 3440124113. The next prime is 3440124161. The reversal of 3440124133 is 3314210443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2209658049 + 1230466084 = 47007^2 + 35078^2 .

It is a cyclic number.

It is not a de Polignac number, because 3440124133 - 2¹³ = 3440115941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3440124098 and 3440124107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3440124113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720062066 + 1720062067.

It is an arithmetic number, because the mean of its divisors is an integer number (1720062067).

Almost surely, 2^3440124133 is an apocalyptic number.

It is an amenable number.

3440124133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3440124133 is an equidigital number, since it uses as much as digits as its factorization.

3440124133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 3440124133 is about 58652.5714099561. The cubic root of 3440124133 is about 1509.5866203195.

Adding to 3440124133 its reverse (3314210443), we get a palindrome (6754334576).

The spelling of 3440124133 in words is "three billion, four hundred forty million, one hundred twenty-four thousand, one hundred thirty-three".