Base | Representation |
---|---|
bin | 100000000010011110… |
… | …111011100011001011 |
3 | 10021210111022020112021 |
4 | 200002132323203023 |
5 | 1030423224313120 |
6 | 23445341225311 |
7 | 2325333040561 |
oct | 400236734313 |
9 | 107714266467 |
10 | 34401401035 |
11 | 1365376a851 |
12 | 6800b62237 |
13 | 33231c8a01 |
14 | 1944c09a31 |
15 | d6523caaa |
hex | 8027bb8cb |
34401401035 has 4 divisors (see below), whose sum is σ = 41281681248. Its totient is φ = 27521120824.
The previous prime is 34401400951. The next prime is 34401401063. The reversal of 34401401035 is 53010410443.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53010410443 = 1783 ⋅29731021.
It is a cyclic number.
It is not a de Polignac number, because 34401401035 - 217 = 34401269963 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3440140099 + ... + 3440140108.
It is an arithmetic number, because the mean of its divisors is an integer number (10320420312).
Almost surely, 234401401035 is an apocalyptic number.
34401401035 is a deficient number, since it is larger than the sum of its proper divisors (6880280213).
34401401035 is an equidigital number, since it uses as much as digits as its factorization.
34401401035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6880280212.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 34401401035 its reverse (53010410443), we get a palindrome (87411811478).
The spelling of 34401401035 in words is "thirty-four billion, four hundred one million, four hundred one thousand, thirty-five".
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