Base | Representation |
---|---|
bin | 100000000010100010… |
… | …000001110100100001 |
3 | 10021210112211111112201 |
4 | 200002202001310201 |
5 | 1030423431310103 |
6 | 23445410453201 |
7 | 2325342662350 |
oct | 400242016441 |
9 | 107715744481 |
10 | 34402213153 |
11 | 13654174a20 |
12 | 6801294201 |
13 | 3323421559 |
14 | 1944d7b997 |
15 | d6534d51d |
hex | 802881d21 |
34402213153 has 8 divisors (see below), whose sum is σ = 42891071040. Its totient is φ = 26806919280.
The previous prime is 34402213151. The next prime is 34402213207. The reversal of 34402213153 is 35131220443.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 34402213153 - 21 = 34402213151 is a prime.
It is a super-3 number, since 3×344022131533 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34402213151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 223390918 + ... + 223391071.
It is an arithmetic number, because the mean of its divisors is an integer number (5361383880).
Almost surely, 234402213153 is an apocalyptic number.
It is an amenable number.
34402213153 is a deficient number, since it is larger than the sum of its proper divisors (8488857887).
34402213153 is a wasteful number, since it uses less digits than its factorization.
34402213153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 446782007.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 34402213153 its reverse (35131220443), we get a palindrome (69533433596).
The spelling of 34402213153 in words is "thirty-four billion, four hundred two million, two hundred thirteen thousand, one hundred fifty-three".
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