Base | Representation |
---|---|
bin | 100000000010100011… |
… | …001011000011100111 |
3 | 10021210120101202000212 |
4 | 200002203023003213 |
5 | 1030424020410002 |
6 | 23445421130035 |
7 | 2325345352043 |
oct | 400243130347 |
9 | 107716352025 |
10 | 34402513127 |
11 | 1365435a334 |
12 | 68013b991b |
13 | 33234c7c58 |
14 | 1945019023 |
15 | d653ac352 |
hex | 8028cb0e7 |
34402513127 has 4 divisors (see below), whose sum is σ = 34449835056. Its totient is φ = 34355191200.
The previous prime is 34402513111. The next prime is 34402513133. The reversal of 34402513127 is 72131520443.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34402513127 - 24 = 34402513111 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34402513093 and 34402513102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (34402513157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23659874 + ... + 23661327.
It is an arithmetic number, because the mean of its divisors is an integer number (8612458764).
Almost surely, 234402513127 is an apocalyptic number.
34402513127 is a deficient number, since it is larger than the sum of its proper divisors (47321929).
34402513127 is an equidigital number, since it uses as much as digits as its factorization.
34402513127 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47321928.
The product of its (nonzero) digits is 20160, while the sum is 32.
The spelling of 34402513127 in words is "thirty-four billion, four hundred two million, five hundred thirteen thousand, one hundred twenty-seven".
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