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344025378433 = 11131363238081
BaseRepresentation
bin1010000000110011000…
…00101010111010000001
31012212222201102222100201
411000121200222322001
521114030444102213
6422013145445201
733566161316332
oct5003140527201
91185881388321
10344025378433
1112299a3a2780
12568114a0801
1326597b4a0a9
141291818c289
158e377806dd
hex501982ae81

344025378433 has 8 divisors (see below), whose sum is σ = 375304846176. Its totient is φ = 312746649600.

The previous prime is 344025378383. The next prime is 344025378461. The reversal of 344025378433 is 334873520443.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 344025378433 - 221 = 344023281281 is a prime.

It is a super-2 number, since 2×3440253784332 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (344025370433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1325953 + ... + 1564033.

It is an arithmetic number, because the mean of its divisors is an integer number (46913105772).

Almost surely, 2344025378433 is an apocalyptic number.

It is an amenable number.

344025378433 is a deficient number, since it is larger than the sum of its proper divisors (31279467743).

344025378433 is a wasteful number, since it uses less digits than its factorization.

344025378433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 369455.

The product of its (nonzero) digits is 2903040, while the sum is 46.

Adding to 344025378433 its reverse (334873520443), we get a palindrome (678898898876).

The spelling of 344025378433 in words is "three hundred forty-four billion, twenty-five million, three hundred seventy-eight thousand, four hundred thirty-three".

Divisors: 1 11 131363 238081 1444993 2618891 31275034403 344025378433